Solve for x. (Answers are in the square brackets; correct if mistaken) Please

l_nxy · #1 (**permalink**) 03-31-2008, 05:37 PM

show working.) *lg = log10? 1) 1 - log2 (6x + 1) = log2 x [1/2]2) lg 4x + 2 - lg (5 - x) = 2 lg 15 [9/5]3) 2 lg 6 + lg x = lg 2 + lg (3x + 1) [1/15]4) lg 5 + lg (2x - 1) = lg 2 + lg (x + 2) [9/8]5) log2 (5 - x) - log2 (x - 2) = 3 [7/3]6) log5 x + log5 (2x - 3) = 1 [5/2]Thanks so much...!

Klaus · #2 (**permalink**) 03-31-2008, 06:26 PM

I am sorry - I won't do your homework for you.